What am I doing wrong in awk with multiple tests?

Shell Programming and Scripting
1 
awk -v pat="$pattern" 'NR == 1 {print $0}; $0 ~ pat {print $0}' infile.csv > outfile.csv

The first row of my file contains headers so I want them. Otherwise, I want only lines containing the BASH variable pattern which I am passing to awk with -v.

This is giving me all the lines containing the pattern but not the first line.

Mike

2

What operating system are you using?

3

Bash 4.1.10(4)
GNU Awk 4.0.2
CYGWIN_NT-6.1 1.7.17

4

Can you show us:

head infile.csv | cat -ev
5

Except for a little IP yes. csv file is unix type EOL

timestamp,sequence_number,alarm_id,alarm_class,resource,logged_by,reference,prev_state,log_action,final_state,alarm_message,generation_time,Comments,Duration,Name,alarm_code $
26-FEB-2013 08:44:08.000,xxxxxx,xxxxxx,EVENT,xxxxxx,xxxxxx,xxxxxx,G,R,R,xxxxxx,26-FEB-2013 08:43:04.000,,64,,NONE,xxxxxx$

Mike

---------- Post updated at 04:30 PM ---------- Previous update was at 04:20 PM ----------

Just to be clear the second rule is working. The first rule (NR == 1) is not.

Mike

6

What is the output of:

awk 'NR==1' infile.csv
7

I had a stupid error in a directory pointer in the surrounding script. Turns out the awk part was working just fine. I can't believe how much time I wasted on that error.

Mike