Use variable in sed don't work.

Shell Programming and Scripting
1

Hi all.

I have a script as below:
cutmth=`TZ=CST+2160 date +%b`
export cutmth
echo $cutmth >> date.log
sed -n "/$cutmth/$p" alert_sbdev1.log > alert_summ.log

My purpose is to run through the alert_sbdev1.log and find the 1st occurence of 'Jan' and send everything after that line to alert_summ.log.

When I execute my script, i get this error:
sed: 0602-403 /Jan/ is not a recognized function.

What is wrong with my script? Please help. Thanks.

2

Place a comma after the last slash:

sed -n "/$cutmth/,$p" alert_sbdev1.log > alert_summ.log

Regards

3

Hi,

I amended my script to below, but still got error.

cutmth=`TZ=CST+2160 date +%b`
export cutmth
echo $cutmth >> date.log
sed -n "/$cutmth/,$p" alert_sbdev1.log > alert_summ.log

Error:
sed: 0602-404 Function /Jan/, cannot be parsed.

Thanks.

4

try this

cutmth=`TZ=CST+2160 date +%b`
export cutmth
echo $cutmth >> date.log
sed -n /$cutmth'/,$p' alert_sbdev1.log > alert_summ.log
5

Hi vidyadhar85,

Thanks! Got it working! =)