To run a local shell script in a remote machine by passing arguments to the local shell script

Shell Programming and Scripting
1

I need to run a local shell script on a remote machine. I am able to achieve that by executing the command

> ssh -qtt user@host < test.sh

However, when I try to pass arguments to test.sh it fails.
Any pointers would be appreciated.

2

Try

> ssh -qtt user@host < 'test.sh YourArgHere'

and let us know how it went.

3

I tried ssh -qtt user@host < 'test.sh 00'
I get an error

test.sh 00: No such file or directory
4

I don't think that will work. Redirection opens a file and feeds its contents to stdin. Arguments are expanded by the shell and supplied to the script as positional parameters. Don't forget the shell runs on the remote host!

5

Any pointers on how I can pass positional parameters to the local script executing on remote machine.

6

You are right; my bad.
What I'd do then, is use here documents to supply the ssh connection with a series of commands. I know for a fact that that indeed works. See this link, and take a look at examples 19-5 and 19-6.

7

Try this one:

ssh -qtt user@host 'sh -s arg1 arg2' < test.sh

and report back if it works...!

2 Likes
8

Hurray it works! Thanks a lot! Please can you let me know why the parameters need to be passed with sh.

ssh -qtt user@host 'sh -s 00' < test.sh

works fine, but if I pass a variable it doesnt resolve the value
Eg:

[iCODE]ssh -qtt user@host 'sh -s "$version"' < test.sh[i/CODE] goes in as $version only.

I got the ssh command to resolve the variable value.

ssh -qtt ${user}@${host} "sh -s "${version}""  <  test.sh

Thanks folks!