The last argument contains spaces, how do I get it into a variable?

Shell Programming and Scripting
21

If you read further down the thread you'll see the 13th argument can be spaces, so unfortunately that doesn't work.

22

Thanks CarloM, this is what I did with your gawk proposal to analyse ${0} and populate the variables V_SEVERITY and V_INFO:

 V_SEVERITY=`echo ${V_MEM_PARAMETERS} | gawk --re-interval '{ matched=match($0," (.{4}) (.{50})$", myarray); if (matched) { print ( myarray[1]);}}'`
 V_INFO=`echo ${V_MEM_PARAMETERS} | gawk --re-interval '{ matched=match($0," (.{4}) (.{50})$", myarray); if (matched) { print ( myarray[2]);}}'`

and these were my results:

NOTE: There should be 56 spaces after vmsdlceref in the argument string, but the forum software strips them.

Note: there should be 51 spaces after 3333 in the argument string.

I probably misadapted the command. Any suggestions?

Zagga

23

echo is compressing/stripping the spaces - try double-quoting the variable ( echo "${V_MEM_PARAMETERS}" )

24

Heartfelt thanks CarloM. I would never have got there in a month of Sundays.