Take action if a particular file appears in a directory

Shell Programming and Scripting
1

This is my task - pls help

Write a script that will run every 5 min and check if a particular file has appeared in a particular directory. Once it appears then rename the file and move it a bkp directory and run another script.

2

Well, it is your task, so what have you tried?

3

to run your script every 5 minutes, you need to schedule a cron job, see - http://www.unix.com/answers-frequently-asked-questions/13527-cron-crontab.html

the script would be something like:

file_to_check="/tmp/newfile"
backup_dir="/foo/"
another_script="/foo/bar"
if [ -e $file_to_check ] ; then
# Check if file exists
  mv $file_to_check $file_to_check.backup    # Rename the file
  mv $file_to_check.backup $backup_dir       # And move it to a backup dir
  another_script   # Run another script
fi
4

THis is my file named mycron which I add it to the crontab entry later to run every 5 mins and this works. But I havnt done the last part - to run another script if everything succeeds.

Thanks for the reply Yogesh. But in ur code, what if the mv fails - ie, say the destination directory doesnt exist or something else ... only after all this succeeds I need to start another script.

#
# Taking action if a particular file appears in a dir
#

filename="/home/mrudula/myfile"

count=`find "$filename" | wc -l`

if [ "$count" -eq 1 ]
then

\# Renaming filename
new_filename="$filename".new
mv $filename $new_filename
echo "$filename" renamed to "$new_filename"

\# Moving to backup directory

bkup_dir="$filename"-bckup
mkdir "$bkup_dir"
mv "$new_filename" "$bkup_dir/$\(basename $new_filename\)"
echo "$new_filename" moved to "$bkup_dir"

else
echo "No file found - "$filename""
fi