stripping leftmost characters from string

Hi there, if i have some strings ie

test_324423
test_242332
test_767667

but I only want the number part (the bolded bit) how do I strip the leftmost 5 characters from the output so that i will have just

324423
242332
767667

any help would be greatly appreciated
Gary

[yogeshs@PS0814 htdocs]$ echo $str
test_324423
[yogeshs@PS0814 htdocs]$ echo $str | cut -d "_" -f 2
324423
[yogeshs@PS0814 htdocs]$

in bash

# v=test_324423
# echo ${v#*_}
324423

This solution is also valid in ksh

Jean-Pierre.

i see, thanks. I don't use ksh much.

that great, thanks guys