string

Shell Programming and Scripting
1

I have 2007-10-03 and I want to write it as 03/10/2007
how can I do this?:confused:

2

[code]
string="2007-10-03"
IFS="-" && echo "$string" | read year month day
string="$day/$month/$year"
echo $string
[/code

3

thanks but it only writes //

and I'm afraid I couldnt understand the part:

IFS="-" && echo "$string" | read year month day

I have a question can I make an array that
its first element is "2"
second element is "0"
third element is "0"
fourth element is "7"
.....

4 
# echo "2007-10-03" | awk 'BEGIN{FS="-";OFS="/"}{print $3,$2,$1}'
03/10/2007
5

thanks :b:

6

You could do this with cut this way:

#!/bin/bash

OLDSTRING="2007-10-03"
YEAR=$(echo "${OLDSTRING}" | cut -d"-" -f1)
MONTH=$(echo "${OLDSTRING}" | cut -d"-" -f2)
DAY=$(echo "${OLDSTRING}" | cut -d"-" -f3)
NEWSTRING="${DAY}/${MONTH}/${YEAR}"

Just another way. Could someone give the awk example?