String manipulation

Shell Programming and Scripting
1

Hello

Could you help with small script:
How to split string X1 into 3 string
String X1 can have 1 or many strings

X1='A1:B1:C1:D1:A2:B2:C2:D2:A3:B3:C3:D3'

This is output which I want to have:

Z1='A1:B1:C1:D1'
Z2='A2:B2:C2:D2'
Z3='A3:B3:C3:D3'
2

can you tell more about the string and what to do?
split after every hex value above D1?
split after every table location pointing to 4th column?

3

One way would be..

[mkt@ michael]$ X1='A1:B1:C1:D1:A2:B2:C2:D2:A3:B3:C3:D3'
[mkt@ michael]$ Z1=$(echo $X1 | cut -d: -f1-4)
[mkt@ michael]$ Z2=$(echo $X1 | cut -d: -f5-8)
[mkt@ michael]$ Z3=$(echo $X1 | cut -d: -f8-)
4

@daWonderer split after every table location pointing to 4th column.
@michaelrozar17 this will not work if i will have more if i have more strings

5

Hi,

I think the below script may full fill your requirement.

#! /bin/bash
c=1
info="A1:B1:C1:D1:A2:B2:C2:D2:A3:B3:C3:D3:A4:B4:C4:D4:A5:B5:C5:D5"
for i in `echo $info | sed 's/\([A-Z0-9]*\):\([A-Z0-9]*\):\([A-Z0-9]*\):\([A-Z0-9]*\):/\1:\2:\3:\4\n/g'`
do
   eval X$c="$i"
   let c=$c+1
done
let c=$c-1
for j in `seq 1 $c`;
do
   eval echo \$X$j;
done

Cheers,
Ranga:)

6

it's possible do with awk ?