Specific search using sed!

Shell Programming and Scripting
1

Hi Guys,
I need to grep a specific string between a pattern. I have used sed command in the past in the following fashion:

set x = ROI_2_AND_mod_AND_name
echo $x | sed 's/.*ROI_\(.*\)_AND.*/\1/'
Returns:
2_AND_mod
I want:
2

But I want just the number "2". All I want is anything between "ROI_ and "_AND" (That is the first AND it sees). Can anybody help?
Thanks in advance.

2

I don't know if sed supports a non-greedy quantifier, but if Perl is an option, then:

$
$ echo $x
ROI_2_AND_mod_AND_name
$
$ echo $x | perl -plne 's/.*ROI_(.*?)_AND.*/$1/'
2
$
$

Alternatively, if the characters between "ROI_" and "_AND" always comprise of digit(s), then you could take advantage of that in your sed command.

3

or awk...

echo $x|awk -F\_ '/ROI_/ {print $2}'

test:

ant2:/regies/test $ echo $look4
ROI_2_AND_mod_AND_name
ant2:/regies/test $ echo $look4|awk -F\_ '/ROI_/ {print $2}'
2
4 
echo $x
ROI_2_AND_mod_AND_name

echo $x | sed 's|^ROI_\(.*\)_AND_mod_.*|\1|'
2
5

try also:

IFS=_ ; set -A ARR $(echo ROI_2_AND_mod_AND_name) ;  echo ${ARR[1]}
6 
echo $x | sed 's/.*ROI_\([^_]\).*/\1/'

--ahamed

7

---------- Post updated at 10:50 AM ---------- Previous update was at 10:49 AM ----------

---------- Post updated at 10:54 AM ---------- Previous update was at 10:50 AM ----------

8

Will it be only numbers and _? Try this...

echo $x | sed 's/.*ROI_\([0-9][0-9_]*\)_.*/\1/'

--ahamed

1 Like
9

This one will return nothing if there is no match

sed -n 's/.*ROI_\(.*\)_AND_mod.*/\1/p'

If the _mod is not a constant one must use a restriction on the matching part in brackets:

sed -n 's/.*ROI_\([0-9][0-9_]*\)_AND.*/\1/p'
1 Like