Shell script to rename a group of files

Shell Programming and Scripting
1

Hello,

I am having 1800 files in a directory with a specified format, like

amms_850o_prod.000003uNy
amms_850o_prod.000003u8x
amms_850o_prod.000003taP
amms_850o_prod.000003tKy
amms_850o_prod.000003si4
amms_850o_prod.000003sTP
amms_850o_prod.000003sBg
amms_850o_prod.000003rvx
amms_850o_prod.000003re7
 
amms_810i_20091021.0510037
amms_810i_20091021.0740001
amms_810i_20091020.1540011
amms_810i_20091020.1710011
amms_810i_20091021.05100310
amms_810i_20091022.0510024
amms_810i_20091021.0510038
amms_810i_20091021.1940001
amms_810i_20091021.1810011
amms_810i_20091021.1440011
 
amms_856i_20100114.1710001
amms_856i_20100118.1210011
amms_856i_20100118.0510024
amms_856i_20100118.0510022
amms_856i_20100115.1810011
amms_856i_20100115.1610001
amms_856i_20100115.1540011
amms_856i_20100115.1410001
amms_856i_20100118.1540013
 
iabs_i_prod.20090921_044434
iabs_i_prod.20090918_042325
iabs_i_prod.20090917_042428
iabs_i_prod.20090916_042342
iabs_i_prod.20090914_042437
iabs_i_prod.20090930_050453
iabs_i_prod.20090929_050508
iabs_i_prod.20090923_040343
iabs_i_prod.20090925_044450
iabs_i_prod.20090928_042431
 
rps_i_prod.20091117165711
rps_i_prod.20091118014217
rps_i_prod.20091118165710
rps_i_prod.20091119021211
rps_i_prod.20091123044331
rps_i_prod.20091124021213
rps_i_prod.20091123170213
rps_i_prod.20091123180001
rps_i_prod.20091123014212
rps_i_prod.20091120021212

in all these file, i need to replace prod with test. As i am new to shell scripting can anyone helpe me in writing a script which does this renaming of files.

Regards,
Bharath.S

2

You only need to rename the files with "prod" in their names? (not all the "files" you listed have "prod" in their names).

ls *prod* | sed "p;s/prod/test/" | xargs -n 2 echo mv

mv amms_850o_prod.000003re7 amms_850o_test.000003re7
mv amms_850o_prod.000003rvx amms_850o_test.000003rvx
mv amms_850o_prod.000003sBg amms_850o_test.000003sBg
mv amms_850o_prod.000003sTP amms_850o_test.000003sTP
mv amms_850o_prod.000003si4 amms_850o_test.000003si4
mv amms_850o_prod.000003tKy amms_850o_test.000003tKy
mv amms_850o_prod.000003taP amms_850o_test.000003taP
mv amms_850o_prod.000003u8x amms_850o_test.000003u8x
mv amms_850o_prod.000003uNy amms_850o_test.000003uNy
mv iabs_i_prod.20090914_042437 iabs_i_test.20090914_042437
mv iabs_i_prod.20090916_042342 iabs_i_test.20090916_042342
mv iabs_i_prod.20090917_042428 iabs_i_test.20090917_042428
mv iabs_i_prod.20090918_042325 iabs_i_test.20090918_042325
mv iabs_i_prod.20090921_044434 iabs_i_test.20090921_044434
mv iabs_i_prod.20090923_040343 iabs_i_test.20090923_040343
mv iabs_i_prod.20090925_044450 iabs_i_test.20090925_044450
mv iabs_i_prod.20090928_042431 iabs_i_test.20090928_042431
mv iabs_i_prod.20090929_050508 iabs_i_test.20090929_050508
mv iabs_i_prod.20090930_050453 iabs_i_test.20090930_050453
mv rps_i_prod.20091117165711 rps_i_test.20091117165711
mv rps_i_prod.20091118014217 rps_i_test.20091118014217
mv rps_i_prod.20091118165710 rps_i_test.20091118165710
mv rps_i_prod.20091119021211 rps_i_test.20091119021211
mv rps_i_prod.20091120021212 rps_i_test.20091120021212
mv rps_i_prod.20091123014212 rps_i_test.20091123014212
mv rps_i_prod.20091123044331 rps_i_test.20091123044331
mv rps_i_prod.20091123170213 rps_i_test.20091123170213
mv rps_i_prod.20091123180001 rps_i_test.20091123180001
mv rps_i_prod.20091124021213 rps_i_test.20091124021213

(remove the echo before mv if that's what you want).

Or look at the rename command, if you have it.

3

Alternatively in bash or ksh93:

ls *prod*|while read i; do mv "$i" "${i/prod/test}"; done
4

Looks good.:b:

5

Thanks for your reply, But when i used the command
ls *prod*|while read i; do mv "$i" "${i/i_prod/t_test}"; done

its giving me the error

"ksh: "${i/i_prod/t_test}": bad substitution"

Can you help in correcting it...

6

I would assume you are using ksh88, not ksh93. What OS are you using?

7

I dont know how to find the version of my OS. can you tell me the command.

8

The question really was which OS (not which version of the OS).

In any case the original xargs solution I posted should work?

9 
uname -a
10

when i execute that command, its gives me the result as
HP-UX hpomt73e B.11.11 U 9000/800 1623329386 unlimited-user license.

11

Hi Atlantis, that is HPUX 11i (v1) . You can use #!/usr/dt/bin/dtksh

12

Its not working even after adding the mentioned line also. so my script looks like

#!/usr/dt/bin/dtksh
ls *prod* | sed "p;s/i_prod/t_test/" | xargs -n 2 echo mv > out1

13

I thought you were going to try it with my line that you modified slightly, since there's where you got the bad substitution error? So:

#!/usr/dt/bin/dtksh
ls *prod* |
while read i; do 
  mv "$i" "${i/i_prod/t_test}"
done

What error did you get with scottn's code?