Shell script to merge the lines between two patterns and print the entire file

Shell Programming and Scripting
2

I think you want to use the a as a state variable, and act according to its state.
First, it must be 6\.4 in a regular expression, because an unescaped dot means "any character".
The action is missing.
If it's to append the current line, then it could be

awk 'a{buf=(buf FS $0)} /Module State/{a=1; buf=$0} /6\.4/{a=0; print buf}' FILE.csv

I use a buf variable:

  • if a == 1 then add the current line to buf with a leading space (append)
  • if Module State is met then set a to 1 and store the line in buf
  • if 6.4 is met then set a to 0 and print buf

In this case it's doable without buffering:

awk 'a{printf " %s", $0} /Module State/{a=1; printf "%s", $0} /6\.4/{a=0; printf "\n"}' FILE.csv
  • if a == 1 then print the current line with a leading space and no ending newline (append)
  • if Module State is met then set a to 1 and print the current line without a newline
  • if 6.4 is met then set a to 0 and print an ending newline

I see opening and closing quotes, so maybe you just need my tip