Shell Script - find, recursively, all files that are duplicated

Shell Programming and Scripting
1

Hi. I have a problem that i can't seem to resolve. I need to create a script that list all the files, that are found recursively, with the same name.
For example if a file exists in more than one directory with the same name it list all the files that he founds with all the info. Could someone help me? Thanks in advance.

2

What have you tried have so far, and how does your code misbehave?

3

I'm sorry i'm stil a noob to shell script. I've been working around find, uniq and sort. But can't really find the solution. :frowning:

4

Check if you have fdupes in your OS.

5

If you dont have fdupes, and if you can write script in Perl.

You can do it easily as,

$hash{"filename"} => [ "absolute-path-of-file", "absolute-path-of-file" ... ]

So which ever file has more than one element in the array, then that are duplicate files !!

6

Inefficient but still took 10 mins for 60,000 files with 200 duplicates. Unsuitable for large numbers of duplicates.

#!/bin/ksh
find . -type f -print|while read F1
do
    basename "${F1}"
done | sort | uniq -d | while read F2
do
    find . -type f -name "${F2}" -exec ls -lad '{}' \;
done