hai
i have a directory lib
in that lib directory i have 10 batch files.
step i have to do is 1) EXECUTE ALL THE FILES by using the command dwarfdump <filename>| grep DW_AT_SUN_command_line
and put the output in one text file.instead of executing the files for all the 10 files .. can i read the files in the directory lib and pass the file name and print the filename and finally the output in the text file..?
how can i do it?
Kindly help .. i am very new to unix..
S
Is this homework? If not,
show us what have you tried so far.
Welcome to forums by the way 
You can tell me
1) how to read all the files in a directory
and i can put that filename into a variable and execute the command >> output.file
Help
S
try this, not efficient though
ls directory_name | while read filename
do
echo $filename
done
ls ./logfile/lib | while read filename
do
echo $filename
dwarfdump $filename | grep DW_AT_SUN_command_line >> dward_output.txt
done
this is giving the output in dwarf_output.txt
but it is better if we have filename at the beginning of outputfile txt. before command execution.
just change this
echo $filename
to
echo $filename >> outputfilename.txt
thanks madhan..
S
when i execute the shell script file dwarf_output.ksh as
ls /logfile/lib | while read filename
do
echo "STARTING THE FILE" $filename >>dwarf_output.txt
echo "*************************************">>dwarf_output.txt
dwarfdump $filename | grep DW_AT_SUN_command_line >>dwarf_output.txt
echo "END OF FILE " $filename >>dwarf_output.txt
done
the output file dwarf_output.txt contains dwarf_output.ksh also. telling
STARTING THE FILE dwarf_output.ksh
*************************************
END OF FILE dwarf_output.ksh
i want to elimate the files starting with .ksh and .sql files.. how can i do this...?
kindly help
S
I guess those are verbose messages.
In that case,
echo "verbose" > /dev/tty
echo "log message" > to_some_log_file
it it not verbose
dwarf_output.ksh is the file where actual shell script is written. so when i execute
ls /logfile/lib | while read filename
do
echo "STARTING THE FILE" $filename >>dwarf_output.txt
echo "*************************************">>dwarf_output.txt
dwarfdump $filename | grep DW_AT_SUN_command_line >>dwarf_output.txt
echo "END OF FILE " $filename >>dwarf_output.txt
done
the scripts execute it's own file. ie
dwarfdump dwarf_output.ksh | grep DW_AT_SUN_command_line
so i dont want .ksh file to execute. how to elimate .ksh and .sql files
S
First, its not a good idea to have bin files (scripts, executable, ..) in the same directory as in directory where data files are available.
Both of them should be abstracted in different directories.
Second,
probably you could check for existence of the literals, '.ksh' or '.sql' in the filename before processing them,
if required string literals are there
then
continue with the next file processing
else
proceed with actual processing
fi
hai
i have idea about filtering the files with find ./ -name "*.ksh" -print
but what is the command for listing all the files without .ksh and .sql files..?
can u pls tell the unix command for this..
waiting
S
Try this:
find . -type f ! \( -name "*.txt" \) ! \( -name "*.sql" \)
Your version of find could differ from mine, if you get errors refer your local find command man page for more information.
if you are want your script not to execute itself, try
ls /logfile/lib | while read filename
do
if [ ! -f dwarf_output.ksh ]; then
echo "STARTING THE FILE" $filename >>dwarf_output.txt
echo "*************************************">>dwarf_output.txt
dwarfdump $filename | grep DW_AT_SUN_command_line >>dwarf_output.txt
echo "END OF FILE " $filename >>dwarf_output.txt
fi
done
or
ls /logfile/lib | while read filename
do
if [ ! -f $0 ]; then
echo "STARTING THE FILE" $filename >>dwarf_output.txt
echo "*************************************">>dwarf_output.txt
dwarfdump $filename | grep DW_AT_SUN_command_line >>dwarf_output.txt
echo "END OF FILE " $filename >>dwarf_output.txt
fi
done