Sh programming

Shell Programming and Scripting
1

I have started writing one script. It is not taking the if block.

Here is the script:

#!/bin/sh
set USER='/usr/ucb/whoami'
 
#######################################################################
#Killing Process
#######################################################################
echo "$USER"
if ("$USER"=="akaur1")
then 
echo 'killing process' >> /apps/jate/qisscript.log
#elif ( "$USER" == "qisadmin") 
#then
#sudo /etc/init.d/jatedaemon.sh stop

fi

When I run this, it is displaying akaur1 at starting, but after that it is giving: TEST_SCRIPT.sh: akaur1: not found

Please help

2

something like this :

if [ $user == "akura1" ];
then
.........
else
........
fi
3

Still same error:
TEST_SCRIPT.sh: [akaur1==akaur1]: not found

4

You need a space after [ and before ].

5

I put a space before and after, now its giving,
TEST_SCRIPT.sh: [akaur1: not found

6

Sorry , it should be :

if [ $user = "akura1" ];
then
.........
else
........
fi
7

Hi,

Pleas chk it out. and you have use single "=" only.

#!/bin/sh
set USER=`/usr/ucb/whoami`

#######################################################################
#Killing Process
#######################################################################
echo "$USER"
if [ "$USER" = "akaur1" ]
then 
echo 'killing process' >> /apps/jate/qisscript.log
#elif ( "$USER" == "qisadmin") 
#then
#sudo /etc/init.d/jatedaemon.sh stop
fi