Hi All,
I am looking for a simple way to write numbers to a file sequentially starting from 1 and ending on a specified upper limit. Example of the output file is below
Example
1
2
3
4
5
.
.
.
.
1000
please let me know the best way to do it.
Is it just me or has the world become too lazy? I'm sure with 115 posts to your name you must have come across the famous for loop, available in a language of your choosing.
many ways to skin your cat...
e.g. bash:
# echo {1..1000}|tr " " "\n">file
using while loop ..
$ i=1; while [ $i -le 100 ]; do echo $i; i=$((i+1)); done
On Linux box, you can use the seq command :
$ seq 5
1
2
3
4
5
$ seq 2 5
2
3
4
5
$ seq 1 2 10
1
3
5
7
9
$
Jean-Pierre.
Hi.
On Linux and other platforms, e.g. freebsd:
vm-freebsd ~ % version =o
OS, ker|rel, machine: FreeBSD, 8.0-RELEASE, i386
vm-freebsd ~ % jot 5 11
11
12
13
14
15
cheers, drl
just another awk ...
awk 'BEGIN{ while (++x<=10)print x; exit}'
Just for fun:
awk '($0=NR)>c{exit}1' c=1000 RS='\000' /dev/zero
@Scruti, you geek
lol 
... by the way, i tested you code in an ubuntu 11 that runs in a VirtualBox, see what i got :
$ awk '($0=NR)>c{exit}1' c=1000 RS='\000' /dev/zero
Processus arr�t�
$ ^C
$ ^C
$
It went into an endless loop, i had to ^C and then wait for 1 minutes before it could break it and give me the prompt back !
@ctsgnb, hehe could not resist :o .The trouble is with RS in [^g]awk , so I think we need to revert to this:
tr '\000' '\n' < /dev/zero | awk '($0=NR)>c{exit}1' c=1000
@Scruti
Yup ! I've just tested it, this code with tr works fine