Hi,
i need find and replace a sting with a new variable having value as spaces in between.
Eg:
set a = "i am variable"
set b = "i am second"
sed -e 's/find_string/'$a'/g' -e 's/find2_str/'$b'/g' input_file
here it is giving error...
How to get an varaible, which is having space..
Thanks in advance,
Vasanth
---------- Post updated at 08:42 AM ---------- Previous update was at 08:33 AM ----------
Hi
anybody there to help me on this issue.
Vasanth
sed "s/find_string/$a/g;s/find2_str/$b/g" input_file
Hi,
i tried the below code
sed "s/find_string/$a/g;s/find2_str/$b/g" input_file
But, variable substituion fails and the replace is coming as $a only. Not the value..
Thans in advance,
Vasanth
And you're sure you used double and not single quotes?
Could you post the output from the following commands:
ps -p$$
set a = "i am variable"
set b = "i am second"
printf "%s\n%s\n" ok ok | sed "s/ok/$a/;s/ok/$b/"
This worked for me..
a="i am variable"
b="i am second"
sed -e "s/find_string/$a/g" -e "s/find2_str/$b/g" input_file