Search the word to be deleted and delete lines above this word starting from P1 to P3

Shell Programming and Scripting
1

Hi,
I have to search a word in a text file and then I have to delete lines above from the word searched . For eg suppose the file is like this:

Records

P1
10,23423432
,77:1
,234:2
P2
10,9089004
,77:1
,234:2
,87:123
,9898:2
P3
456456
P1
:123,456456546
P2
abc:324234
,89237494
P3
,98:234
.
.
.

and so on.

The file contains thousands of records.

Now I have to search for a particular word for eg I am searching 9089004. Then the records in which 9089004 will lie I mean from P1 till P3 will be deleted from the file and rest of the records will exist in the file. The problem is that the word can exist anywhere between P1 to P2 or from P2 to P3 and then I have to delete that record i.e. from P1 to P3.

Please help

2

See if this works for you:

#!/usr/bin/ksh
rm -f temp_file
rm -f out_file
mP1="N"
while read mLine; do
  mTag=$(echo ${mLine} | cut -c1-2)
  if [[ "${mTag}" = "P1" ]]; then
    mP1="Y"
  fi
  if [[ "${mP1}" = "Y" ]]; then
    echo ${mLine} >> temp_file
  else
    echo ${mLine} >> out_file
  fi
  if [[ "${mTag}" = "P3" ]]; then
    mStr=$(egrep '9089004' temp_file)
    if [[ "${mStr}" = "" ]]; then
      cat temp_file >> out_file
    fi
    rm -f temp_file
    mP1="N"
  fi
done < inp_file
3

Thanks for your reply ...... shell_life .....

It is working fine , but I am getting P3 records above P1

For eg the input file is:

If I am searching the number 9881119347

P1
123
P2
9881119347,87
P3
9881119347
P1
998811347
P2
34534
P3
98811147
P1
78686
P2
902384930284
P3
2904898

Then the output generating is:

9881119347
P1
998811347
P2
34534
P3
98811147
P1
78686
P2
902384930284
P3
2904898

But it should be like below:

P1
998811347
P2
34534
P3
98811147
P1
78686
P2
902384930284
P3
2904898

I am searching only till P3..but I have to search before the next P1 occurs...Please check the output that is required.

Kindly advice