Search for Pattern and Print including Lines in between

Gurus,

I have a big file that needs to be sorted out and I cant figure out what to do. The file name is as below:

Name: xxxx yyyy nnnn
Description: dfffgs  sdgsgsf hsfhhs
afgghhjdgj
fjklllll   gsfhfh
Updated: jafgadsgg gsg
Corrected: date today

The file consists of line like these.

I want to only print out the line with the "Name" and "Updated" including all the lines between them.

Appreciate your help.

awk '$1=="Update:"{f=0}$1=="Name:"{f=1}f' file

awk "/Name/,/Updated/" file

or:

sed -n '/Name/,/Updated/p' file

It works wonders! Thanks so much

sed -nf scr input.txt

scr contains:

/Name:/,/Updated:/{
w abc.txt
}

input.txt contains:

Name: xxxx yyyy nnnn
Description: dfffgs  sdgsgsf hsfhhs
afgghhjdgj
fjklllll   gsfhfh
Updated: jafgadsgg gsg
Corrected: date today

output ie abc.txt contains:

Name: xxxx yyyy nnnn
Description: dfffgs  sdgsgsf hsfhhs
afgghhjdgj
fjklllll   gsfhfh
Updated: jafgadsgg gsg

Here w writes into a file.

$ ruby -ne 'print if /Name/../Updated/' file

what if i dont want the "Updated" included? like it will only print lines from "Name" until before "Updared"?

Still want to sort it?

awk '/Update/{f=0}/Name/{f=1}f' file

when i ran danmero code, i got from line Name to before updated :

awk '$1=="Updated:"{f=0}$1=="Name:"{f=1}f' file

is that what you wanted?

i just want to get an output of:

Name: xxxx yyyy nnnn
Description: dfffgs  sdgsgsf hsfhhs
afgghhjdgj
fjklllll   gsfhfh

without the "Updated" line.

---------- Post updated at 09:44 AM ---------- Previous update was at 09:35 AM ----------

i've got syntax error "bailing out near line 1"

---------- Post updated at 09:44 AM ---------- Previous update was at 09:44 AM ----------

i've got syntax error "bailing out near line 1"

hi,
as per this you might be using old one for awk.
please try using nawk instead of awk.

sed -n '
/Name/,/Updated/{
/Updated/!p
}
' file

the nawk works! thanks