Script to delete sudo access in redhat 5.4

Shell Programming and Scripting
1

Hi ,
This site is veryhelpful in resolving many issues.I have a request to delete sudo access for 3 users say user1,user2,user3 from around 50 servers in redhat 5.4.I know it is very time consuming to login to each server and delete entry in /etc/sudoers file.Is there any way can i do it using a script.
Appreicate your response on it.Advance thanks for your replies.

2

To get you started.

#!/bin/bash

server_list=(10.0.0.25)
regex="user1\|user2\|user3"

for((i=0; i< ${#server_list[@]}; i++))
do
    ssh root@${server_list[$i]} "sed  -i.bak \"/$regex/d\" /etc/sudoers"
done

Note : -i is included which will edit the file inline, which also creates a backup file. Once you confirm this works locally, then you can go ahead with full fledged.

HTH

3

Hi ahamed101 thansk for your reply.I have tried below script.after execution it deleted few other id's along with the mention 3 user id's.I have restored sudoers file again from the backup.

i think it is not taking user names from the list it seems.I have tried below script but it has given following result.

#!/bin/bash
server_list=(server1)
regex="sagbhat\|ralavudi\|bratinm"
for((i=0; i< ${#server_list[@]}; i++))
do
    ssh root@${server_list[$i]} "sed  -i.bak \"/$regex/d\" /etc/sudoers"
done

output:
It deleted few other id's

[root@server1 etc]# cat /etc/sudoers|grep kgough
[root@server1 etc]# cat /etc/sudoers|grep llewis
[root@server1 etc]# cat /etc/sudoers|grep bpadhi

appreciate your help on this.Thanks

4

Try with

regex="^user1\|^user2\|^user3"
5

Hi Tried with below option but no luck.It didn't work.

regex="^user1\|^user2\|^user3"