removing a column from list

Shell Programming and Scripting
1

What I am trying to do is figure out how to remove a column from a list in a file, or from the command line.

The opposite of cut -cX-Y file1

The file contains (result of who command)

jhabi0 pts/ta Oct 8 16:22
llemo0 pts/1 Oct 8 15:30
rgood0 pts/2 Oct 8 16:30
llemo0 pts/3 Oct 8 15:31
jlinc0 pts/tb Oct 8 16:31
rgood0 pts/4 Oct 8 16:10
jhabi0 pts/te Oct 8 09:17
cpacni pts/tf Oct 8 15:32
grenci pts/5 Oct 8 13:57
rhowa0 pts/th Oct 8 12:05
mmaha0 pts/tk Oct 8 15:40
grenci pts/7 Oct 8 13:58

and I would like to retrieve everything except (cut -c7-21)

 pts/ta
 pts/1
 pts/2
 pts/3
 pts/tb
 pts/tc
 pts/td
 .
 .

Thanks in advance

2

Sorry to anyone who gave this a thought. I just played around with the cut command and figured it out.

>who | cut -c1-7,31-38

gives me the login name and time logged in.

3

i would lean toward awk.

who|awk '{ print $2 }'

4

Actually this is what I had in mind.

who | awk '{ print $1 FS $5}'

Thanks for the awk lesson