QUESTION...simple program?

Applications Programming
1

I am new to the unix/linux environment.
AND........
I need to create a mini shell..that displays prompt (i.e., READY:$), accepts a command from std-in, and prints the command and any parameters passed to it. HELP!!!!

2

I think you can try the simple code:

----------------------------------------------------------------------------
#!/usr/bin/ksh

agreed=
while [ x$agreed = x ]; do
printf "Ready:$>"
read receive
ksh -c "$receive"
echo
echo "Do you want to continue? [yes or no] "
read reply leftover
case $reply in
y* | Y*)
agreed=;;
n* | N*)
echo "*** Shell Terminate ***";
exit 1;;
esac
done
--------------------------------------------------------------------------------

3

Thank you so much for helping me out.

I'm trying to write this in the C language. So far I have this:

#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
#include <iostream.h>

main()
{
cout<<"You have entered my 1814 shell"<<endl;
bool exit=true;
char *line[10];
int n=0;
getline(line[n]);
while (!(exit))
{
line[n]=0;
cout<<"READY:#";
cout<<"The command you typed was: " <<line[0];
execv(line[0],NULL);
}
}

ANYbody.....Everybody... :confused:

4

You are welcome.

I think I encounter a strange thing.My code can run normally on sun solaris OS. I swear.

I wonder if you can tell me your platform.SCO UNIX?HP UNIX?
Perhaps the bug is caused by the version of unix OS.

I modified the code.If you input the "exit",You can quit the shell.

-------------------------------------------------------------------
#!/usr/bin/ksh

agreed=
while [ x$agreed = x ];
do
printf "Ready:$>"
read receive
if [ "$receive" = "exit" ]
then
exit 1;
fi
ksh -c "$receive"
done
--------------------------------------------------------------------

5

it's running on Sun OS 5.8

6

Your program is writed in C Plus Plus language,not C .
But I think there are some problems with it. I modifed your code according to your thinking.

----------------------------------------------------------
#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
#include <iostream.h>

#include <string.h>

main()
{
cout<<"You have entered my 1814 shell"<<endl;
bool exit=true;
char line[1024]; /* Command String */
int n=0;

while \(\(exit\)\)
\{
    cout&lt;&lt;"READY:\#";
    int iRet;
    cin.getline\(line,sizeof\(line\)\);
    /* If you input "exit",you will quit the shell  */
    if\(strcmp\(line,"exit"\) == 0\)\{
        cout&lt;&lt;"*** Shell End ***"&lt;&lt;endl;
        break;
    \}
    system\(line\);
    cout&lt;&lt;"\\n";
    cout&lt;&lt;"The command you typed was : "&lt;&lt;line&lt;&lt;endl;
    cout&lt;&lt;"\\n";
    line[0] = 0;
\}

}

-------------------------------------------------------------------------

7

thanks for everything. A version I wrote the other day works, and yours works even better. Now i'm having trouble with a daggone fork and execve command. it works, but not perfectly.

8

What's wrong?

9

i posted my new problem under the "Fork()ing Hell!" thread. you can read allllll about it there :smiley: