Problem with `find ...`

Shell Programming and Scripting
1

Hi all,
Have the following snippet of code that I'm having trouble trying to work ...

The snippet of code is running on our Production Server and the intent is to copy the second most recent IDE file across from the Development Server.

I have the following files defined in $DEVLOC ...

-rw-r--r--   1 root       sys         245751 Aug  1 09:23 050729.14:20.ides.zip
-rw-r--r--   1 root       sys         245751 Aug  1 09:23 050729.14:32.ides.zip
-rw-r--r--   1 root       sys         245751 Aug  1 09:23 050729.15:18.ides.zip
-rw-r--r--   1 root       sys         245751 Aug  1 09:23 050729.15:28.ides.zip
-rw-r--r--   1 root       sys         247925 Aug  1 09:23 050730.00:05.ides.zip
-rw-r--r--   1 root       sys         249305 Aug  1 09:23 050731.00:05.ides.zip
-rw-r--r--   1 root       sys         253966 Aug  1 09:23 050801.00:06.ides.zip
-rw-r--r--   1 root       sys         121667 Aug  1 23:18 050802.00:05.ides.zip
-rw-r--r--   1 root       sys         128756 Aug  2 19:31 050803.00:05.ides.zip
-rw-r--r--   1 root       sys         131843 Aug  3 19:27 050804.00:05.ides.zip
-rw-r--r--   1 root       sys         137142 Aug  4 13:44 050805.00:05.ides.zip
-rw-r--r--   1 root       sys         143807 Aug  5 19:33 050806.00:05.ides.zip
-rw-r--r--   1 root       sys         146817 Aug  6 21:22 050807.00:05.ides.zip
-rw-r--r--   1 root       sys         146817 Aug  6 21:22 050808.00:05.ides.zip
-rw-r--r--   1 root       sys         150047 Aug  8 23:34 050809.00:05.ides.zip
-rw-r--r--   1 root       sys         155809 Aug  9 23:17 050810.00:05.ides.zip

I'm tried (in vain) initially to assign the most recent file, but business now requires second most recent (for QA reasoning).

I'm sure that I'm missing something really simple; just need a kick in the pants to have someone point it out for me; not having used `find` in scripts prior.

IDEtoFind=`find $DEVLOC -name \*.ides.zip -mtime -01 -print`
echo "Finding : $DEVLOC/$IDEtoFind" >>$templog
echo "Finding : $DEVLOC/$IDEtoFind"
echo "Copying : $DEVLOC/$IDEtoFind" >>$templog
echo "     To : $tmp/$downloadfile" >>$templog
echo "Copying : $DEVLOC/$IDEtoFind"
echo "     To : $tmp/$downloadfile"
cp $DEVLOC/$IDEtoFind $tmp/$downloadfile || error_copy

Any pointers would be of great assistance.

2

For 2nd most recent file, try:
ls -t | sed '1d;2q'

3

Thanks for the reply Perderabo.

Reading this ...
a) Display files with most recent first.
b) with sed '1d;2q'
i. "1d" - delete first value
ii. "2q" - quit sed with value of second

Is that a reasonable estimate?

4

Yes that is right.

From the man pages of sed,

q      Immediately quit the sed  script  without  processing  any  more
              input,  except  that  if  auto-print is not disabled the current
              pattern space will be printed.

Vino

5

Many thanks for the confirmation Vino.