program name--test
#!/bin/bash
output1=`/home/user/a.c`
output2=`/home/user/a.c`
k=`$output1 + 1`
m=`$output2 + 1`
echo $k
echo $m
---------------------------------------------------------------------------
prgram name--a.c
#include<stdio.h>
int main()
{
int i,j;
printf("Enter Values ::");
scanf("%d %f",);
snprintf(s, 100, "echo %d","echo %d",i,j);
system(s);
return 0
}
-------------------------------------------------------------------------
my requirement is to access the variable from C program as a simple input,pass the value of two variables to the script
which will manipulate the value and display
main thing is : not to execute c Program first,.we have to excute ./test first in console
Problem is I did not pass those two variable to the script.
Is there any way to pass the value of those variable from C program?please help me out...i an sending error message..thanks to all
[user@localhost ~]$ chmod 777 a.c
[user@localhost ~]$ chmod 777 test
[user1@localhost ~]$ ./test
/home/user/a.c: line 3: syntax error near unexpected token `('
/home/user/a.c: line 3: `int main()'
/home/user/test.c: line 3: syntax error near unexpected token `('
/home/users/test.c: line 3: `int main()'