Printing with decimal places from last 4 digits

Shell Programming and Scripting
1

I have input file like below,

201424|9999|OSS|622010|RGT|00378228764
201424|8888|OM|587079|RGT|00284329675
201424|7777|OM|587076|RGT|00128671024
201424|6666|OM|581528|RGT|00113552084

Output should be like below, should add decimal (.) from last 4 digits.

201424|9999|OSS|622010|RGT|0037822.8764
201424|8888|OM|587079|RGT|0028432.9675
201424|7777|OM|587076|RGT|0012867.1024
201424|6666|OM|581528|RGT|0011355.2084

Please help me on this..

Thanks,
Vinoth

2

Using sed:

sed 's/[0-9][0-9][0-9][0-9]$/.&/' infile

and if your sed supports extended regular expressions:

sed -r 's/[0-9]{4}$/.&/' infile
3

Thanks Chubler it works ..