printing portion of the output usind sed/awk

Shell Programming and Scripting
1

friends, i am a newbie in scripting. could someone help me in selecting only the last column of below ps command output ?

mqm 14 16466   0   Sep 15 ?           0:01 /opt/mqm/bin/runmqlsr -r -m QMGR.INBOUNDSSL -t TCP -p 1415 -i 5.1.26.5
     mqm 12 16700   0   Sep 15 ?           0:00 /opt/mqm/bin/runmqlsr -r -m QMGR.EUMEA -t TCP -p 1414 -i 10.1.122.10
     mqm 11 16472   0   Sep 15 ?           0:00 /opt/mqm/bin/runmqlsr -r -m QMGR.INBOUND -t TCP -p 1416 -i 5.1.26.5

I am looking for below output only :-

/opt/mqm/bin/runmqlsr -r -m QMGR.INBOUNDSSL -t TCP -p 1415 -i 5.1.26.5
/opt/mqm/bin/runmqlsr -r -m QMGR.EUMEA -t TCP -p 1414 -i 10.1.122.10
/opt/mqm/bin/runmqlsr -r -m QMGR.INBOUND -t TCP -p 1416 -i 5.1.26.5

using either grep/awk/sed.any pointers are highly appreciated.

2 
echo 'mqm 14 16466 0 Sep 15 ? 0:01 /opt/mqm/bin/runmqlsr -r -m QMGR.INBOUNDSSL -t TCP -p 1415 -i 5.1.26.5' | sed 's#[^/]*\(/.*\)#\1#'

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3

Another one:

<command> | sed 's_[^/*]*__'
4

a typo I reckon - you don't need an 'inner' '*':

<command> | sed 's_[^/]*__'
5

thanks a lot vgersh99,Franklin52 for quick and prompt response.hmm I need to really understand the command now..