Printing all lines before a specific string and a custom message 2 lines after

Shell Programming and Scripting
1

Hello all,

I need to print all the lines before a specific string and print a custom message 2 lines after that.

So far I have managed to print everything up the string, inclusively, but I can't figure out how to print the 2 lines after that and the custom message.

My code thus far is:

'{a[NR]=$0} ($3 ~ "Bob") {for(x=1; x<=$1; x++) {print a[x]}}'

My data is similar to the following:

Don|Joe|Lue
Mary|Elane|Bob
David|Mark|Steven
John|Jim|William
Sal|Jose|Michael

I would like to get the following result once "Bob" is matched:

Don|Joe|Lue
Mary|Elane|Bob
David|Mark|Steven
John|Jim|William
STOPPING HERE          #This being the custom message

Thanks in advance

2 
awk "/Bob/{c=3}--c==0{print "Message"; exit}1" file
3

By sed..

sed '/Bob/{n;n;n;s/.*/Stopped here/;q}' inputfile > outfile
4 
awk -F\| '1;$3=="Bob"{c=3};--c==0{print "STOPPING HERE"; exit}' infile
5

Many thanks