Hello Guys,
I am working on a script and using the below code to fetch the list of all repositories
repolist()
Output of the above code is
BSB CIB COB DCI DIB DSB ESB-P ESB-TOOLS FareVerify GCACHE GWY IBMSOAMB IBMSOAWAS ISM KESTREL-DEV kestrel-migration KESTREL-UAPI KESTREL-XD LAMB LinuxAutomation MGLNO PORTAL repos4 SCMTools SESTOKEN SMB SOA SPLASH SSB STP TOI
Diretory from where I am fetching the list
Now my question is how I make this list in the format or output
1.BSB 2.CIB 3.COB 4.DCI 5.DIB 6.DSB 7.ESB-P 8.ESB-TOOLS 9.FareVerify 10.GCACHE 11.GWY 12. IBMSOAMB 13.IBMSOAWAS 14.ISM 15.KESTREL-DEV 16.kestrel-migration 17.KESTREL-UAPI 18.KESTREL-XD 19.LAMB 20.LinuxAutomation 21.MGLNO 22.PORTAL 23.repos4 24.SCMTools 25.SESTOKEN 26.SMB 27.SOA 28.SPLASH 29.SSB 30.STP 31.TOI
and also If I want to check the codebase of the above repository I want to select it with numbering options like 1 to 31(1....31 the number of repositry)
Thanks in advance
Try this.. not tested
repolist()
{
cd ${CHDIR}
Repo=`ls|cut -d " " -f1`
count=0
echo "$Repo" | while read line; do count=`echo $count + 1 | bc`; echo -n " $count : $line "; done
}
thanks this code is working fine for me but my script 2nd option "Check for Repository latest codebase" need repository name but I don't want this I want the user just only enter the option like 1 to 31(1....31) neither name of the repositiry.Please suggest.
1)BSB 2)CIB 3)COB 4)DCI 5)DIB 6)DSB 7)ESB-P 8)ESB-TOOLS 9)FareVerify 10)GCACHE 11)GWY 12)IBMSOAMB 13)IBMSOAWAS 14)ISM 15)KESTREL-DEV 16)kestrel-migration 17)KESTREL-UAPI 18)KESTREL-XD 19)LAMB 20)LinuxAutomation 21)MGLNO 22)PORTAL 23)repos4 24)SCMTools 25)SESTOKEN 26)SMB 27)SOA 28)SPLASH 29)SSB 30)STP 31)TOI
Enter options from 1 to 4
1 Check for Repository list
2 Check for Repository latest codebase
3 Check for Repository User's list for contributors and users
4 Exit
Select Menu Number [ 1 - 4 ]:
Press 2 and
Enter the repository name :
i dont understand your request
My request is let suppose if you have a script.I run that script and it gives the below prompt then I want to enter the repo. number not repo. name that I get from above code.
1.BSB 2.CIB 3.COB 4.DCI 5.DIB 6.DSB 7.ESB-P 8.ESB-TOOLS 9.FareVerify 10.GCACHE 11.GWY 12. IBMSOAMB 13.IBMSOAWAS 14.ISM 15.KESTREL-DEV 16.kestrel-migration 17.KESTREL-UAPI 18.KESTREL-XD 19.LAMB 20.LinuxAutomation 21.MGLNO 22.PORTAL 23.repos4 24.SCMTools 25.SESTOKEN 26.SMB 27.SOA 28.SPLASH 29.SSB 30.STP 31.TOI
Enter the repository name :28(for example)I don't want to use repo. name here
something like this ?
repolist()
{
cd ${CHDIR}
Repo=`ls|cut -d " " -f1`
echo "Enter the REPO # : "
read usrInput
count=0
echo "$Repo" | while read line; do count=`echo $count + 1 | bc`; echo " $count : $line "; done | grep $usrInput
}
getting the below output.i need to restrict it to a single value . as in grep when i give 3 it will search for 3, 13, 23 etc (where 3 appears) . i need it to display only a single value corresponding to that number.
BSB
Now I am getting the desired result for my script
repolist() { cd ${CHDIR} Repo=`ls|cut -d " " -f1` echo "Enter the REPO # : " read usrInput count=0 echo "$Repo" | while read line; do count=`echo $count + 1 | bc`; echo " $count : $line "; done | grep $usrInput|head -1 }
output
Enter the REPO number(1,2...):23
Can u help me to cut the above output
Thanks in advance
---------- Post updated at 06:52 PM ---------- Previous update was at 06:20 PM ----------
Now I have also got the desired output through cut commnand
Thank you very much for your kind help
---------- Post updated at 11:24 PM ---------- Previous update was at 06:52 PM ----------
Hello Guys,
The output of my file is below and I want to delete those lines from the file where these kind of numbers (e.g. 11.2.13.1)are coming.Highlighted in red
BSB/
Thanks in advance
Below is the code but I need one more thing here.This code works fine and list the repo with numbers.I need here is
I want to restrict the person to enter 0(zero) as well as to enter exceed than count .i.e. if count=56 and if he enters 57 it should not work and same for 0 because here
repocodebase()
List of repo:-
1)BSB
Thanks-
repocodebase()
{
echo -en "Enter the REPO number(1,2...):"
read usrInput
count=0
fileName="/home/e030809/temp.txt2"
while read line; do count=`echo $count + 1 | bc`; echo " $count)$line "; done < $fileName
[ "$usrInput" -le "$count" -o "$usrInput" -ne "0" ] && grep -w $usrInput > /home/e030809/temp.txt3 || echo "No Repo Exists"
}
kshji
July 28, 2011, 1:13am
13
Example to use select. Ksh93 and bash support it. Like for except give the selection prompt.
cd $CHDIR
PS3="Your choice (ENTER=menu again, e=end):"
select f in *
do
[ "$REPLY" = "e" ] && break
echo "Choice: ($REPLY) $f"
[ ! -f "$f" ] && echo "not regular file" >&2 && continue
echo $f
# if like to exit after 1st selection, then add line break
# break
done
I tried your code but I don't why it's not working when I enter 0 it doesn't give me
repocodebase()
output
[e030809@vhldvsmsv001 ~]$ ./test
Thanks-
Its working but again there is one problem
while I am giving the right output it's not store any thing in file temp.txt3
code in my file is
repocodebase()
format of temp.txt2