Need sequence no in the grep output

Shell Programming and Scripting
1

Hi,

How to achieve the displaying of sequence no while doing grep for an output.

Ex., need the output like below with the serial no, but not the available line number in the file

S.No  Array   Lun 
1       AABC  7080
2       AABC  7081
3       AADD  8070
4       AADD  8071
5       DDEE  1044
6       DDEE  1055
2

So the above is your desired output, but what does the input file look like?

3

Hello,

Assuming that you want to search a particular pattern and then you want to count the particular search sequences. Here is the example for same.

Input file:
$ cat check_file_check12111
col1   col2      col3        col4   col5        col6      col7
21     66745     rs1234      21     rs5678      23334     0.89
21     66745     rs2334      21     rs9978      23334     0.89
23     66745     rs3334      21     rs7578      23334     0.89
24     66745     rs6664      21     rs9998      23334     0.89
21     66745     rs8884      21     rs5588      23334     0.89

Code to get the requested output will be.

awk 'BEGIN{ print "S No.""\t""data" } $1 ~ 21 {print ++i"\t"$0}' check_file_check12111

Output will be as follows.

S No.   data
1       21     66745     rs1234      21     rs5678      23334     0.89
2       21     66745     rs2334      21     rs9978      23334     0.89
3       21     66745     rs8884      21     rs5588      23334     0.89

This is just an example there are sevral ways to grep the patterns, please be more specific in your requirement to get the exact Output.

Thanks,
R. Singh

4

You could also use cat -n :

$ grep "^21" check_file_check121111 | cat -n
     1  21     66745     rs1234      21     rs5678      23334     0.89
     2  21     66745     rs2334      21     rs9978      23334     0.89
     3  21     66745     rs8884      21     rs5588      23334     0.89