Need Regular expression

Shell Programming and Scripting
1

Hi,

I want to find the records using grep with following conditions.

one field position at 26 and having length 2 and values of 21,24,31,34 or
another field position at 28 and length 2 of values 21,224,31,34

I wrote it like below, But I want this search using grep, can any one provide?

awk 'substr($0,26,2)==21 || substr($0,26,2)==24 || substr($0,26,2)==31 || substr($0,26,2)==34 || substr($0,28,2)==21 ||substr($0,28,2)==24||substr($0,28,2)==31 ||substr($0,28,2)==24{print $0}' R3AP200811_GMSSMSTRLD_01358_20081119235959.traf_load

Regards,
Venkat

2

i'm not sure to understand why you say toy use grep, if i understandign you i think you need cut:

while read line 
do
var=`echo $line |cut -c26,27 `
var2=`echo $line|cut -c28,29 `

if [ $var -eq $NUMBER1 -o $ var2 -eq $NUMBER1 ..................................... ]
then
  ...............
else
  ...............
fi
done< file
3 
grep -E '^.{25}(21|24|31|34)(21|24|31|34)' file
4

This way you ignore OR. With your code both fileds (26-27) AND (28-29) have to be true. If I understud it good, it�s enought that one condition is satisfied.

 
grep -E "^.{25}((21|24|31|34)..|..(21|24|31|34))" file
5

Or, a shorter version that takes advantage of the cross product:

grep -E "^.{25}([23][14]..|..[23][14])" file

tyler_durden