need help with nawk using -v vars

Shell Programming and Scripting
1

I'm trying to pass nawk a shell variable to be used in a pattern match. I can't get this work.

I'm calling nawk from a /bin/sh

echo " Input file: \c"
read var1
echo " Input: \c"
read var2

nawk -F"|" -v x=$1 ' BEGIN
$15 ~ /^'$var2'/ {print $2}' var1 {apary=$15; bparty=$23; time=$4; duration=$43; account=$65; charge=$66}
END { print apary"|"bparty"|"vrijeme"|"duration"|"account"|"charge } ' $1 >> final

so I should read from file var1 and search for pattern var2 and put all that in file final.

PLEASE can anyone help me out with this code somehow it does not work..

THANKS in advance

2

perhaps ...

echo " Input file: \c"
read var1
echo " Input: \c"
read var2


nawk -F"|" -v x=$1 ' BEGIN 
$15 ~ /^'$var2'/ {print $2}' var1 {apary=$15; bparty=$23; time=$4; duration=$43; account=$65; charge=$66}
END { print apary"|"bparty"|"vrijeme"|"duration"|"account"|"charge } ' $1 >> final

Please, give us an example

Jean-Pierre

3

hello guys I finallly solved that problem...

it should be like this

nawk -F"|" -v x=$2 '
BEGIN { print "A party|B party|Vrijeme|Duration|AccountBalance|Charge|" }
{ if($15 ~ /'$2'/) {{apary=$15; bparty=$23; vrijeme=$4; duration=$43; account=$65; charge=$66}
{ print apary"|"bparty"|"vrijeme"|"duration"|"account"|"charge }}
}
END {print "bla bla bla "} ' $1 >>$2

so output should be just fiields 15 23 4 43 65 and 66 and comprered with value on field $15..

Thanks all for reading this post

4

echo " Input file: \c"
read var1
echo " Input: \c"
read var2
nawk -F"|" -v x1=$var1 -v x2=$var2 -v etc ....{
# x1 and x2 are the variables to use here
}