need help with awk programming

Shell Programming and Scripting
1

Hello Friends

I want to process only those lines which are not started with a * or "

example File name:
GRX

"RxDataTime, NSysClkEn, Frame","Size","Sleep","TNum","TSet","TWait"
*Init Start
*Comment Generated from: C:\Documents and Settings
000000,0000,1,0,0,0,0,0,0
000000,0000,0,0,0,0,0,0,0

In the file I only want to process only the last two lines..
I need a help badly..

Thanks in advance..
user_pradyu

2

Two methods using grep

grep -v '^\*' filename | grep -v '^\"'

egrep -v '^\*|\"' filename
3

Many many thanks for the reply ,,but when I merge it with a gawk or nawk it seems to processing all the lines..

like

#!/usr/bin/ksh -f

egrep -v '^\*|\"' GRX | 
gawk '
  {
    print $0
} ' GRX

it displays me all the lines in the file..

4

I am not sure what exactly you are looking for. Why gawk/awk is required here?
egrep -v '^\*|\"' GRX should give teh expected result.
Is my understanding correct?

5

hi,

Follow code can filter out all your desired lines. Just put all your logic in the pring section, then it will only deal with those lines.

code:

awk '$0 !~ /^"/ && $0 !~ /^\*/{
print
}' filename
6

First of all I want to applogize if I explained wrongly..

Thank you very much for the code ,, That exact code I needed..
Hats of to you brilliants..

Now I m merging that with my code..

Hope your kindness remain the same always..

user_prady

Again I m facing some problem with implementing function in it ..
like

gawk '
BEGIN{}
$0 !~ /^"/ && $0 !~ /^\*/{
print ...
function my_function(){}
}' filename

Please help ....

7

[quote="user_prady,post:6,topic:178389"]
First of all I want to applogize if I explained wrongly..

Thank you very much for the code ,, That exact code I needed..
Hats of to you brilliants..

Now I m merging that with my code..

Hope your kindness remain the same always..

user_prady

[quote]

Is it not possible to define my own function ??

:frowning:

8

put your function outside the action block

gawk '
BEGIN{}
$0 !~ /^"/ && $0 !~ /^\*/{
print 
}
function my_function()
{
 print "echo"
}
' filename
9

I got that where I was wrong..

Thanks a lot ... Atlast I got what I wanted ..Thank you very much for your valuable time ..

Regards,
Pradyumna