mv command to rename multiple files that retain some portion of the original file nam

Shell Programming and Scripting
1

Well the title is not too good, so I will explain.

I need to move (rename) files using a simple AIX script.

???file1.txt
???file2.txt
???file1a.txt
???file2a.txt

to be:

???renamedfile1'date'.txt
???renamedfile2'date'.txt
???renamedfile1a'date'.txt
???renamedfile2a'date'.txt

The ??? are realy numbers 001 through 999, and there are two filenames per number. The 'date' is easy `date +%Y%m%d`. but due to my limited scripting ability, I cannot seem to get this accomplished.

Any help would be greatly appreciated.

Thanks in advance.

2

Something like this? Try it first without the coloured portion to see if you get the right commands:

ls ???file??.txt | sed "s/\(...\)\(.*\)\.\(.*\)/mv & \1renamed\2""`date +%Y%m%d`"".\3/" | sh

Regards

3

It works greatly on UBUNTU

ls ???file*.txt | sed "s/\(...\)\(.*\)\.\(.*\)/mv & \1renamed\2`date +%Y%m%d`.\3/" | sh
4

For whatever reason (did a copy and paste of the line into a script) this did not work. I only got one file with a `date +%Y%m%d`.txt

for f in *pepfilled.txt ; do
mv $f /usr/$fclaims`date +%y%m%d`.txt
done

Am I missing a quote(s) somewhere? The red claims above is the new file name with a format of ???claims20081220.txt, renamed from ???pepfilled.txt.

This will get half my files ???pepfilled.txt, I will just write the same script for the other half ???pepfilledcr.txt.

5

You provided weak examples, in your first post, of the input and the desired output. Try this:

ls ???pepfilled*.txt | sed "s/\(...\).*\.\(.*\)/\1claims`date +%Y%m%d`.\2/" | sh

Regards