Multi line log files to single line format

Shell Programming and Scripting
1

I want to read the log file which was generate from other command . And the output was having multi line in log files for job name and server name. But i need to make all the logs on one line

Source file

07/15/2018 17:02:00                               TRANSLOG_1700     Server0005_SQL     Missed
07/15/2018 17:02:00                               TRANSLOG_1700     Server20048_SQL     Missed
07/15/2018 17:02:00                               TRANSLOG_170-     Server30009-CE-     Missed
                                                   0_Server30009       DBS0009_SQL
07/15/2018 17:02:00                               TRANSLOG_170-     Server30009-CE-     Missed
                                                   0_Server30009-      DBS0009V9_S-
                                                   V9                QL

Need Output like this

07/15/2018 17:02:00  TRANSLOG_1700     Server0005_SQL     Missed
07/15/2018 17:02:00  TRANSLOG_1700     Server20048_SQL     Missed
07/15/2018 17:02:00  TRANSLOG_170-0_Server30009     Server30009-CE-DBS0009_SQL     Missed
07/15/2018 17:02:00  TRANSLOG_170-0_Server30009-V9     Server30009-CE-DBS0009V9_S-QL     Missed
2

Try

awk '
NF < 5          {T[3] = T[3] $1
                 T[4] = T[4] $2
                 next
                }
                {if (T[1]) print T[1], T[2], T[3], T[4], T[5]
                 split ($0, T)
                }
END             {print T[1], T[2], T[3], T[4], T[5]
                }
' OFS="\t" file
07/15/2018	17:02:00	TRANSLOG_1700	Server0005_SQL	Missed
07/15/2018	17:02:00	TRANSLOG_1700	Server20048_SQL	Missed
07/15/2018	17:02:00	TRANSLOG_170-0_Server30009	Server30009-CE-DBS0009_SQL	Missed
07/15/2018	17:02:00	TRANSLOG_170-0_Server30009-V9	Server30009-CE-DBS0009V9_S-QL	Missed
1 Like
3

Great thanks working fine