Listing the file name and no of records in each files for the files created on a specific day

Shell Programming and Scripting
1

Hi,

I want to display the file names and the record count for the files in the 2nd column for the files created today.

i have written the below command which is listing the file names. but while piping the above command to the wc -l command
its not working for me.

ls -l --time-style='+%d/%m/%Y' | grep '06/05/2014' |  awk '{print $7}'

 Need suggestion to  get the file name and record count of the files.

Thanks

2

try

for file in $(ls -ltr | grep "May  6" | awk '{print $9}');
do
 rc=`cat $file | wc -l`
 echo $file $rc
done
3

Thanks so much . But i want it in a command not using script. if possible.

4

How about

find . -type f -mtime -1 -exec wc -l {} +
5

Thanks a lot Rudic. Its almost satisfied my requirement But along with the files created today it is also listing one more file which was created one day before.

Anyway thanks. I will explore more on -mtime and will get the solution.

Thanks for your time.

6

Look into -mmin as well, and -daystart if available on your system.