Is there a command or better combination of cmds that will give me the list of Unix users in a particular Unix group whether their primary group is that group in question (information stored in /etc/passwd) or they are in a secondary group (information stored in /etc/group).
So far all I got is a combination of the following:
groupName=XXXXX
groupId=$( getent group | egrep "^${groupName}:" | cut -d: -f3 )
getent passwd | egrep "^.*:.*:.*:${groupId}" | cut -f1 -d:
getent group | egrep "^${groupName}:" | cut -f4 -d:
(Yeah for all you NIS and/or LDAP guys, I did use the getent commands)
#!/usr/bin/env python
d={}
for line in open("/etc/group"):
line=line.strip().split(":")
users=line[3]
if users:
for u in users.split(","):
d.setdefault(u,[])
d.append(line[0])
for i,j in d.iteritems():
print "%s is in groups: %s" %(i,j)
output
# ./test.py
daemon is in groups: ['bin']
user5 is in groups: ['dialout', 'video']
user2 is in groups: ['dialout', 'video']
user3 is in groups: ['dialout', 'video']
user1 is in groups: ['dialout', 'video']
nobody is in groups: ['nogroup']
groupName="$1"
# Save some processing, no need to call getent so much.
#
groupEntry=$(getent group | grep "^${groupName}:")
if [ ! "$groupEntry" ]; then
echo "Group $groupName does not exist." >&2
exit 1
fi
# Note it IS possible that the same group is found in a local /etc/group
# as well as another source, you'll get two results. We'll assume the
# first one wins.
#
groupId=$(echo "$groupEntry" | cut -d: -f3 | head -1)
# A username could be in a primary group and have that SAME primary
# group redundantly set as a secondary group.
#
passwdUser=$(getent passwd | cut -d: -f1,4 | grep ":${groupdId}$" | cut -d: -f1)
echo "${groupEntry},${passwdUser}" | cut -d: -f4 | tr ',' '\012' | sed '/^$/d' | sort -u
Thanks everyone, the operating system is Solaris and the "logins -g <grp>" command works BEAUTIFULLY and provides some visibility on primary vs secondary groups, like the following:
