Hi folks
I use a Solaris 10 box with Bash shell.
I have here a script (it works!) to list all scripts in crontab which contains the string "sqlplus":
for i in $(ls `crontab -l | grep -v '#' | awk '{ print $6 }' | grep -v '^$'`); do grep -l 'sqlplus' "$i"; done
Is there a more elegant solution? How would you do?
You could probably do the whole thing with awk but I think this is a little bit nicer:
grep -l sqlplus $( crontab -l | awk '/^#/d {print $6 }' )
edit: only thing is if you have no cron jobs it will grep from stdout so perhaps a redirect from null for this special case:
grep -l sqlplus $( crontab -l | awk '/^#/d {print $6 }' ) < /dev/null