Limited log on specific timelines

Linux and Unix-Like Linux
1

Hi Gurus,

We have a very huge size log files (around 3-4 GBs), in which all the versions (nothing but a log entries) of orders would be saved... It is very hard to find out the exact piece of log for a specific order (by moving the cursor or by searching with specific key words in vi).

I know the timelines of the order and the log file also will be having the time entry at the start of each line like below.

I want to grep the lines that are logged between a specific timelines...
For ex: From "08:21:39" to "08:30:00"

Can someone help me with the exact awk/grep options to grep the lines based on time zones..

Thanks for help in advance.

Regards,
VRN

2

Try,

awk '/08:21:39/,/08:30:00/ {print}' file
1 Like
3

Thanks much for the reply.

Its working... but could you let me know the way for searching the keawords in same way... For Ex: I want to find out all the logs between two specific keywords...

awk '/'12345 version 1'/,/'12345  version 2'/ {print }' file

But it dint work...

Kindly assist

4

Too many ' in there. Just keep the outermost ones.

---------- Post updated at 14:38 ---------- Previous update was at 14:37 ----------

And, make sure both strings exist and second comes after first.

5 
awk '/12345 version 1/,/12345  version 2/ {print }' file

I tried above, it didnt work.....

Somehow below one is also not working....

awk '/03:05:37/,/03:07:18/ {print }' file

It is taking the first value correctly and fetching the data from "03:05:37", but it is not taking the second value and giving result till end of file.

Can someone advice on above pls?

Regards,
VRN

6

Do those strings exist LITERALLY in the input file? I can see version 2 has two separating spaces vs. one in version 1 's case.
Please post the result of

awk '/12345 version 1/' file
awk '/12345  version 2/' file
awk '/03:07:18/' file