Hi all, i have a perl script. from within the perl script, i am calling a system command which i need to pass in a perl variable. but the variable substitution does not seems to happen. would like to find out where is the missing escape character or extra quotes;or what is my mistake.
#!/usr/bin/perl -w
$community="public";
$result=system("snmpwalk -v 2c -c $community localhost system");
$result would contain the exit status that is returned by snmpwalk command.
from the man pages:
The return value is the exit status of the program as returned by the wait call.
To get the actual exit value, shift right by eight (see below). See also exec.
This is not what you want to use to capture the output from a command, for that you should use merely backticks or qx//, as described in "`STRING`" in perlop.
Return value of -1 indicates a failure to start the program or an error of the wait(2) system call (inspect $! for the reason).
If you are trying to capture the output of snmpwalk command, then use backticks instead:
$snmpwalk_out = `snmpwalk -v 2c -c $community localhost system`;
Hi Yogesh Sawant,
the backtick worked. thank you.