I'd like to be able to identify in which column a string occurs. So far I know that I can tell how many columns there are and how to return a specific column:
$ sar -r | grep 'kbswpcad' | awk 'NF = 9 { print $NF }'
%swpused
I've even managed to get the columns to output to an array but I think this is over complicated:
$ sar -r | head -3 | tail -1 | tr -s [:blank:] " " | awk '{ split($0, head, " ") } END { for (i in head) print i, " : "head }'
4 : %memused
5 : kbbuffers
6 : kbcached
7 : kbswpfree
8 : kbswpused
9 : %swpused
10 : kbswpcad
1 : 00:00:01
2 : kbmemfree
3 : kbmemused
Using the above I still can't do a string check on the array element.
So, in short, how find out which column %swpused is in?
Thanks in advance