Identify if ran by su or sudo?

Recently I was on an operational call and heard the people running my code placing the code in the /tmp directory and running as root. I had not planned on that. So I want to add some checks to my code (using ksh93):

# ---------- ---------- ----------
# root not allowed to run this
# ---------- ---------- ----------
[[ $( whoami ) = root ]] && exit 2

# ---------- ---------- ----------
# Don't run this in /tmp
# ---------- ---------- ----------
[[ $( pwd ) = /tmp* ]] && exit 3

# ---------- ---------- ----------
# Don't run as sudo
# ---------- ---------- ----------


# ---------- ---------- ----------
# How much space is available here?
#
# Filesystem    Type   1K-blocks      Used Available Use% Mounted on
# /dev/sda3     ext3    68588072  32259392  32788356  50% /home
# ---------- ---------- ----------
integer _avail=$( df -k . | grep -v "^Filesystem" | awk '{ print $4 }' )
integer _threshold=26214400  # 25GB
(( _avail < _threshold )) && {

    print -u2 "***> There is not enough space (25gb) on this mount point!"
    print -u2 "     Only found ${_avail} kb."
    exit 4

}

What I can't find is a means to check the case where my code was run with sudo or "su -". The above 'whomai' returns the users name, not the fact it was run with root access through sudo. There are many reasons to use sudo, but in this case I want my app to run as a normal user with normal permissions, no extra help.

Is this possible? any ideas? I've done some google searching and all the references I can find are on how to use sudo, not how to identify it is being used.

Thanks for any help.
Eric

ant:/home/vbe $ whoami
root
ant:/home/vbe $ who am i
vbe        pts/2        May 19 10:25
>whoami
eric

>sudo echo $( whoami )
eric

How do I know that sudo was being used?

$ echo $(id -u)
1000
$ sudo echo $(id -u)
0

==>

[ $(id -u) -eq 0 ] && exit 2
# or
$(($(id -u))) || exit 2