i get stuck here . Anyone could check my work?
the user type a group of upper case letters at a time with 0 at the end. Find and display the first letter in alphabetic order.
For example, input of F, G, K, S, U, G, D, Q, P , the result should be D
Any invalid input character (eg. #, $, 3, a, etc.) should cause an error message and be ignored.
echo "please enter an alphabet"
input3=1
echo "" > temp
while [ "$input3" != "0" ]; do
read input3
echo $input3 > check
if [ "$input3" != "0" ]; then
if [ check1=`grep -w "[A-Z]" check ]; then
echo $input3 >> temp
else
echo input should be upper case alphabet
fi
fi
done
grep -w "[A-Z]" temp > temp1
echo the first letter in alphabetic order is `sort temp1 | head -1`;;
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---------- Post updated at 10:51 AM ---------- Previous update was at 09:11 AM ----------
#!/usr/bin/ksh
TMP="bla"
# Clean up old temp file
clean_up()
{
if [[ -e $TMP ]]; then
rm $TMP
fi
}
clean_up
echo "Enter one upper case character per line and hit enter; to stop enter a zero."
while :; do
read INPUT
case $INPUT in
[A-Z]) echo $INPUT >> $TMP
;;
0) echo '------ OUTPUT ------'
sort $TMP| uniq| head -1
break
;;
*) echo "no upper case letter and/or more than 1 character!"
;;
esac
done
clean_up
exit 0
Enter one upper case character per line and hit enter; to stop enter a zero.
3
no upper case letter and/or more than 1 character!
d
no upper case letter and/or more than 1 character!
F
s
no upper case letter and/or more than 1 character!
S
h
no upper case letter and/or more than 1 character!
$
no upper case letter and/or more than 1 character!
p
no upper case letter and/or more than 1 character!
P
0
------ OUTPUT ------
F
I guess you did not use ksh - I have the same problem like you on bash. Not sure why though. When using ksh like in the shebang (#!/usr/bin/ksh) all is fine. Maybe someone else knows why, sorry.
Update:
Found a way in bash - change the line inside the case/esac to:
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