How to print a value in the variable using awk ?

Hi All,

I have a part of a script below:

var1="value1"
awk 'BEGIN {printf("%36s \n ","value1")}'

Instead of directly giving the "value1" , I need to give using "var1" in the above awk statement.

Is this possible?
If so, what is the modified awk command?

Thanks in advance
JS

Same logic that the other example:

awk 'BEGIN {printf("%36s \n ","'"${var1}"'")}'