How to input "EOF" signal?

Applications Programming
1

How to input "EOF" signal?

#include<stdio.h>
int main(int argc,char *argv[])
{
     int c,i;
     i=0;
    while((c=getchar()) != EOF )
    {
        if(c=='\n')
            ++i;
    }
     printf("%d\n",i);
}

How to input an "EOF" signal ? to gain the value of "i";Thanks.:slight_smile:

2

I think in Unix ctrl + d will work

1 Like
3

I execute the program in Debian. It had no response when input "Ctrl D" and was interrupted when input "Ctrl Z" in terminal. :o How to print the value of i?

4

Strange, Ctrl+D should have worked. With Ctrl+Z, you've sent the program into the background, suspending its execution, so there won't be any more output (check the output of ps -ef , and you'll see them floating around).

1 Like
5

This is a program from K&R.

after executing you should type couple of lines as input, and then hit ctrl+D.

Then this will output number of lines you have entered.

1 Like
6

Thanks.I try it."Ctrl+D" worked.
By the way, for the first time, gcc shows

"linker input file unused because linking not done"

,what's meaning? Thanks in advance.

7

post the gcc command you have executed.

8

Ok,here

gcc -Wall -o file file.c
9

I am not sure exactly what causes this problem. But you can ignore this as you just started with simple programs and not linking any libraries while compiling.

Can you try

gcc -c -Wall -o file file.c

. This command is producing the same error as you posted.

But without option "-c" it works fine for me. (this option stops the compiler from invoking the linker. But you have not mentioned this option but still getting this error seems to odd.

10

Thanks,I know.:b: