hi,
Pls advice me, how to grep only the ip address from the following output:
<ip>10.4.65.67</ip>
for example:
Scott
November 5, 2009, 6:55am
2
sed -n "s+<ip>\(.*\)<.*+\1+p" file1
10.4.65.67
10.4.65.67
10.4.65.172
10.4.65.46
10.4.65.46
10.4.65.237
10.4.65.79
10.4.65.79
Or if your awk support this:
awk -F"[<>]" '/ip/ { print $3 }' file1
10.4.65.67
10.4.65.67
10.4.65.172
10.4.65.46
10.4.65.46
10.4.65.237
10.4.65.79
10.4.65.79
or
awk -F"</*ip>" '/ip/ { print $2 }' file1
try...
cat file | grep "<ip>" | awk -F "[<ip></ip>]" '{print $5}'
The solution of scottn is better....i have to learn a lot....
Hi
grep "ip" <filename>|cut -f2 -d"<"|cut -f2 -d">"
Regards,
---------- Post updated at 07:27 AM ---------- Previous update was at 07:17 AM ----------
Hi Scottn,
May i request you to explain the command u have send
awk -F"[<>]" '/ip/ { print $3 }' filename - why "/ip/" need to mentione over here?
sed -n "s+<ip>\(.*\)<.*+\1+p" filename - i could not understand...
Regards,
grep -e '^[1-9][0-9]\.[1-9][0-9]\.[1-9][0-9][]0-9]\.[1-9][0-9][]0-9]' file
Scott
November 5, 2009, 8:44am
6
If awk supports it you can specify more than one field separator (-F"[<>]") or field separators with more that one character or with regular expressions ("</*ip>"). And I only want lines with ip in them (/ip/)
Better maybe would have been
$2 == "ip" { print $3 }
remember everything after "<ip>" ( \(.*\) ) and before the next (actually the last) "<", and then print it "...\1p"
OK if you want the whole line with the IP address in it. And I can't see a dot (.) on any other line, so based on the input file
grep \\. file
would have done the same thing.
awk '/ip/{gsub(/<ip>|<\/ip>/,"");print}' file
