Hi Friends ,
Sorry if this is a repeated question ,
The input file contains 5 lines , so the the values of the variables i and count should b
i=5;
count=15
but the variables are not updating , the value of variables showing i=0 and count =0 only.
can any1 help me please.
Updated code below..
count=0
i=0
while read line
do
i=`expr "$i" + 1`
count=`expr "$count" + "$i"`
done < input.txt
echo " i Value =$i "
echo " Count Value = $count"
Output
i Value =5
Count Value = 15
count= `expr $count + $i`
=>
count=`expr $count + $i`
Setting variable must the whole set to be in 1st argument.
Which shell you are using ?
If you have not old bsh, then you can write without using external expr.
Always add the correct shell to the 1st line in script, no need to take care of your interactive "keyboard" shell and for us it's easier to give solution.
#!/bin/ksh
count=0
i=0
while read line
do
(( i=i+1 )) # or (( i+=1 ))
(( count = count + i ))
done < input.txt
echo " i Value =$i "
echo " Count Value = $count"
Hi Palse,
Thanks For u r reply , i tried the same but the variables are not updated.
i value = 0
count value = 0
and iam using the bash shell
Did you try this ?
#!/bin/bash
count=0
i=0
while read line
do
(( i=i+1 )) # or (( i+=1 ))
(( count = count + i ))
done < input.txt
echo " i Value =$i "
echo " Count Value = $count"
echo "my input file:"
cat input.txt
> cat temp.bash
count=0
i=0
while read line
do
i=`expr "$i" + 1`
count=`expr "$count" + "$i"`
done < input.txt
echo " i Value =$i "
echo " Count Value = $count"
> bash temp.bash
i Value =5
Count Value = 15
Sorry, i able to execute the same code in bash shell too.
Note : Did you given the variables with in double quote, Pls check
hii Palse,
sorry the variable values are not updating , let me post the code which i have written ( as u said)
#!/bin/bash
count=0
i=0
while read line
do
i=`expr "$i" + 1`
count=`expr "$count" + "$i"`
done < input.txt
echo " i value = $i";
echo " count value = $count";
and output is :
-bash-3.00$ sh readLine.sh
i value = 0
count value = 0
What do u say ?
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Thank You.
The UNIX and Linux Forums
chmod a+rx readLine.sh
and execute it.
When you say
sh script, you will use sh, not script 1st line shell, and it looks that your sh is something, not bash or ksh.
If you like to run using bash then call
bash readLine.sh
Two method to run script:
chmod a+rx somescript
1st line:
#!/usr/bin/some_interpreter
ex. to run:
./somescript
interpreter inputfile
ex. bash bashscript
Thanks dude.
check this
my shell is bash
echo $SHELL
/bin/bash
so iam using bash shell , and u said i changed the permissions to the file as a+x , still the output not showing the updated variables .
but when i run the script with
"bash readLine.sh"
It is showing the correct output .
correct me if i'm wrong.
---------- Post updated 07-21-09 at 01:04 PM ---------- Previous update was 07-20-09 at 04:57 PM ----------
Thanks Dude
i use bash and your original script works fine. are you sure "input.txt" contains lines? or does it even exists?
-bash-3.2$ ./test
i Value =5
Count Value = 15
-bash-3.2$ cat test
count=0
i=0
while read line
do
i=`expr $i + 1`
count=`expr $count + $i`
done < input.txt
echo " i Value =$i "
echo " Count Value = $count"
-bash-3.2$ ./test
i Value =5
Count Value = 15
-bash-3.2$
Thanks buddy,
ya input.txt has lines , and u r code working fine ..
Thanks a lot guys .. keep the spirit