How to get process name from PID?

UNIX AIX
1

HI,

i used

ps -ef | grep 3539052 | grep -v grep

and i got a output like ths

root  3539052  3407918   0   May 07      - 709:31 /usr/sbin/syslogd

but what i need is instead of full path /usr/sbin/syslogd i want only the process name that is 'syslogd' here.

2 
echo $(basename $(ps -ef | grep 3539052 | grep -v grep|awk '{print $8}'))

Should do the trick

1 Like
3

thanks sea....its workin for me

4

This should work in AIX (although only able to test is on BSD and RHEL):

ps -p 3539052 -o comm=

For example:

[root@ns1 /]# ps -ef | grep [1]471
root      1471     1  0 08:02 ?        00:00:00 /sbin/rsyslogd -i /var/run/syslogd.pid -c 5
[root@ns1 /]# ps -p 1471 -o comm=
rsyslogd
1 Like