How to generate cntl+c interrupt through script?

Shell Programming and Scripting
1

Hi all,

can anyone tell me how to generate control+c interrupt through shell script.

2 
kill SIG

... need to find the corresponding SIG (kill -l)

kill -s INT $$

?

break (get out of a loop)
or
exit (get out the script)

3

Are you trying to terminate another process? If so, use kill and look and the values to set in the man pages for signal.

Are you trying to recognise a user pressing CNTL-C? If so, you have a few options:-

stty -isig

This will ignore all interupts from the keyboard. This may be a little heavy handed though, so you could trap the CNTL-C and handle it in your script. The line

trap "echo \"You hit CNTL-C\"" INT

early in the script will display the message and continue. You could grow it into

trap "echo \"`date` You hit CNTL-C\"" INT

You can also use the command (the bit in quotes) to call a function or do something else, but that is for you to decide what logic you want to perform such as

#!/bin/ksh
cheeky()
{
echo "You hit CNTL-C trying to break out of my code you cheeky thing."
echo "I'm going to reduce your salary by �10."
((salary=$salary-10))
}

trap "cheeky" INT

..... and the main logic flows here

You may need to get the variables exported if your wish to have a function do something, but I hope that this gives you a start.

Robin
Blackburn/Liverpool
UK