Hi!
I just want to count number of files in a directory, and write to new text file, with number of files and their name
output should look like this,,
assume that below one is a new file created by script
Number of files in directory = 25
1. a.txt
2. abc.txt
3. asd.dat
----------------
----------------
----------------
----------------
----------------
----------------
25. last file.dat
ls | cat -n > new_file
This should do
1 a.txt
2 abc.txt
.......
......
25 last file.dat
Thank You..
Have you got the first line?? 
No I haven't
Can we break this into two lines?
echo "Number of files in the directory = `ls -ltr | grep -v '^d' | wc -l`
ls -ltr | grep -v '^d' | cut -c 59-100 | awk '{ print NR". "$0}'
Hi..
Your script could able to find number of files in a directory, but not able to write it into file...
You will have to redirect into a file.
echo "Number of files in the directory = `ls -ltr | grep -v '^d' | wc -l` >file
ls -ltr | grep -v '^d' | cut -c 59-100 | awk '{ print NR". "$0}' >>file
result is wrong..my dear..
If you are deploying awk anyhow, why don't you do it extensively:
ls -l|awk '/^-/{Ar[++n]=$9} END {print "No. of files: ", n; for (i=1;i<=n;i++) print i".", Ar}'
So, can we have the folder details??
---------- Post updated at 04:04 PM ---------- Previous update was at 03:59 PM ----------
Thanks RudiC 
So I agree that the above code will work. What if the file name contains <space>?
UNIX systems doesn't allow that naming, but windows does. Even the O/P provided at the beginning has such a name.
You are right - what I posted was thought to be an example/hint on how to improve, not a full blown solution. You'd need to concatenate ALL trailing fields into Ar to account for that, like AR[++n]=$9" "$10... or Ar[++n]=substr($0,50) . Neither of these is really satisfying. I'd prefer to use sth. like stat on systems where it is available.
stat -c"%F %n" *| awk -F"\t" '/^regular/{Ar[++n]=$2} END {print "No. of files: ", n; for (i=1;i<=n;i++) print i".", Ar}'
admin@las:~/Desktop/file_make/datafilter$ stat -c"%F %n" *| awk -F"\t" '/^regular/{Ar[++n]=$2} END {print "No. of files: ", n; for (i=1;i<=n;i++) print i".", Ar}'
No. of files: 7
1.
2.
3.
4.
5.
6.
7.
---------- Post updated at 06:29 AM ---------- Previous update was at 06:28 AM ----------
This is using awk
admin@las:~/Desktop/file_make/datafilter$ ls -l|awk '/^-/{Ar[++n]=$9} END {print "No. of files: ", n; for (i=1;i<=n;i++) print i".", Ar}'
No. of files: 7
1. a.txt
2. data_filter.sh
3. data_filter.sh~
4. data_filter.txt
5. data_filter.txt~
6. dir.sh
7. dir.sh~
stat -c"%F %n" *|
^--- You need a <TAB> char here!
file names are not coming..
Pls post the output of the stat cmd alone.
Shell script approach, you have to pass absolute path as argument to this script:-
#!/bin/ksh
_DIR=$1
_SEQ=1
if [ $# -ne 1 ]
then
echo "Usage: <script> <absolute path>"
exit 1
fi
dir_count=$( find "${_DIR}" -path "${_DIR}/*" -prune -name "*" -type f | wc -l )
if [ $dir_count -ne 0 ]
then
echo "Number of files in directory: $_DIR = $dir_count"
for file in $( find "${_DIR}" -path "${_DIR}/*" -prune -name "*" -type f )
do
echo "${_SEQ}. $( basename $file )"; _SEQ=$( expr $_SEQ + 1 )
done
else
echo "No files found in directory: $_DIR"
fi
Try this, using -1 option of ls :
~/unix.com$ ls -1 | awk '{A[NR]=$0}END{print "Number of files in directory = "NR; while(i++<NR)print i"."A}'
find . -maxdepth 1 -type f -printf "%f|" | awk '{printf "Number of files: %s\n",NF;gsub(/\|/,"\n")}1' FS="|"
You can try this..Suppose vikram.txt is your file in which you want to save all the file and the number of files .
#!/bin/sh
vikram=$(ls |grep -v vikram.txt | wc -l)
vikram1=$(echo "Number of files ="$vikram"")
echo $vikram1 > vikram.txt
ls | grep -v vikram.txt | cat -n >> vikram.txt