how many pass in the file ,three question

Shell Programming and Scripting
1

Hi all
Question 1:
I want to use "awk" or "sed" to know how many "PASS after "FINISH"
i
Question 2:
I want to use "awk" or "sed" to know how many "PASS" after the *last* "FINISH ,it shoud be 2 in this file

Question 3.
I want to use "awk" or "sed" to know how many "PASS between "789" and "12345"

Thanks for your help

2

See the following commands.

Ans1:

grep -c "PASS" fine_name

 sed -n '/PASS/p' fine_name | wc -l

Ans2:

cat fine_name | tr "\n" " " | sed -r "s/(.*) (FINISH.*)/\2/g" | tr " " "\n" | grep -c "PASS"

Ans3:

sed -n '/789/,/12345/p' fine_name | grep -c "PASS"
3

Thanks for the quick answer. for the first one, I want to know how many "PASS" after FINISH, you tell me total num of PASS in the file

4

See the following code. to count the total number of "PASS" after matching the first occurrence of the "FINISH"

sed -n '/FINISH/,$p' pass | grep -c "PASS"
5

Using awk,

awk '/PASS/ &&  c++ && 0 END { print c; }' file

awk '/FINISH/ { f=1 } /PASS/ && f++ && 0 END { print f-1; }' file

awk '/789/,/12345/ { if(/PASS/) {c++;} }END { print c }' file
6

thanks all