echo "1337124526" | perl -pe 's/(\d+)/easttime($1)/e'
the above gives a date and time.
how can i subtract the date and time given by this command, from the current present date?
can this be a one liner or as close to a one-liner as possible?
You get now with:
date +%s
so all you really need is:
echo "($(date +%s) - 1337124526)/(60*60)" | bc -l
Result in hours.
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